document.write( "Question 116294: Three numbers added together total 68. The second number is four more than the first, the third number is twice the first. find the numbers. \n" ); document.write( "

Algebra.Com's Answer #84567 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Three numbers added together total 68.
\n" ); document.write( "x + y + z = 68
\n" ); document.write( ":
\n" ); document.write( "The second number is four more than the first,
\n" ); document.write( "y = x + 4
\n" ); document.write( ":
\n" ); document.write( "the third number is twice the first.
\n" ); document.write( "z = 2x
\n" ); document.write( ":
\n" ); document.write( "find the numbers.
\n" ); document.write( "x + y + z = 68
\n" ); document.write( "Subsitute
\n" ); document.write( "x + (x+4) + 2x = 68
\n" ); document.write( "x + x + 4 + 2x = 68
\n" ); document.write( "4x = 68 - 4
\n" ); document.write( "4x = 64
\n" ); document.write( "x = 64/4
\n" ); document.write( "x = 16
\n" ); document.write( ":
\n" ); document.write( "y = 16 + 4 = 20
\n" ); document.write( "z = 2(16) = 32
\n" ); document.write( ":
\n" ); document.write( "Check: 16 + 20 + 32 = 68 \n" ); document.write( "

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