document.write( "Question 1207665: Find the real solutions by factoring.\r
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document.write( "x(x^2 - 3x)^(1/3) + 2(x^2 - 3x)^(4/3) = 0\r
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document.write( "I factored out (x^2 - 3x)^(1/3).\r
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document.write( "(x^2 - 3x)^(1/3)[x + 2(x^2 - 3x)^(4/9)]\r
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document.write( "Stuck here.... \n" );
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Algebra.Com's Answer #845663 by ikleyn(52814)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " You factored incorrectly; making errors, you created difficulties for yourself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " A correct factoring is below.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(x^2-3x)^(1/3) * [x + 2*(x^2-3x)^(3/3)) = 0,\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( "(x^2-3x)^(1/3) * (2x^2-5x) = 0.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It deploys in separate equations\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " (a) x = 0\r\n" ); document.write( "\r\n" ); document.write( " (b) x - 3 = 0\r\n" ); document.write( "\r\n" ); document.write( " (c) 2x - 5 = 0\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "with elementary solutions.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |