document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116184>Question 116184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem. The perimeter of a rectangle is 62 m. If the width were doubled and the length were increased by 21 m, the perimeter would be 120 m. What are the length and width of the rectangle?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84566 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) 2L+2w=62<BR>\n" );
document.write( "B) 2(L+21)+2*2w=120<BR>\n" );
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document.write( "B) <BR>\n" );
document.write( "2L+42+4w=120<BR>\n" );
document.write( "2L+4w+42-42=120-42<BR>\n" );
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document.write( "2L+4w=78<BR>\n" );
document.write( "2L+2w=62<BR>\n" );
document.write( "---------Subtract<BR>\n" );
document.write( "===>2w=16<BR>\n" );
document.write( "2w/2=16/2<BR>\n" );
document.write( "w=8 m<BR>\n" );
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document.write( "A) <BR>\n" );
document.write( "2L+16=62<BR>\n" );
document.write( "2L+16-16=62-16<BR>\n" );
document.write( "2L=46<BR>\n" );
document.write( "2L/2=46/2<BR>\n" );
document.write( "L=23 m<BR>\n" );
document.write( ". <BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );