document.write( "Question 1207661: Find the real solutions of the equation. \r
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\n" ); document.write( "\n" ); document.write( "2x^(-2) - 3x^(-1) - 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "I then decided to rewrite the original equation this way:\r
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\n" ); document.write( "\n" ); document.write( "(2/x^2) - (3/x) - 4 = 0\r
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Algebra.Com's Answer #845657 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i did the following:\r
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\n" ); document.write( "\n" ); document.write( "let k = x^-1\r
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\n" ); document.write( "\n" ); document.write( "x^-2 = x^-1 * x^-1 = k * k = k^2\r
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\n" ); document.write( "\n" ); document.write( "2x^(-2) - 3x^(-1) - 4 = 0 becomes:\r
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\n" ); document.write( "\n" ); document.write( "2k^2 - 3k - 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "factor by using quadratic formula to get:\r
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\n" ); document.write( "\n" ); document.write( "k = -.8507810594 or 2.350781059.\r
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\n" ); document.write( "\n" ); document.write( "since k = x^-1, then:\r
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\n" ); document.write( "\n" ); document.write( "x^-1 = -.8507810594 or 2.350781059.\r
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\n" ); document.write( "\n" ); document.write( "this means that 1/k = -.8507810594 or 2.350781059.\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get:\r
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\n" ); document.write( "\n" ); document.write( "k = 1/.8507810594 or 1/2.350781059.\r
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\n" ); document.write( "\n" ); document.write( "k becomes 1.17539053 or .4253905297.\r
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\n" ); document.write( "\n" ); document.write( "round as necessary.\r
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