document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207662>Question 1207662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If k = (x + 3)/(x - 4) and k^2 - 3k = 28, find x. \r<BR>\n" );
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document.write( "I say replace every k with (x + 3)/(x - 4).\r<BR>\n" );
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document.write( "I get this:\r<BR>\n" );
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document.write( "[(x + 3)/(x - 4)]^2 - 3[(x + 3)/(x - 4)] = 28\r<BR>\n" );
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document.write( "Correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845653 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> that looks reasonable, although it might get messy.\r<BR>\n" );
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document.write( "you can also do the following:\r<BR>\n" );
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document.write( "in the equation  k^2 - 3k = 28, subtract 28 from both sides to get:<BR>\n" );
document.write( "k^2 - 3k - 28 = 0<BR>\n" );
document.write( "factor this quadratic equation to get:<BR>\n" );
document.write( "(k-7) * (k+4) = 0<BR>\n" );
document.write( "solve for k to get:<BR>\n" );
document.write( "k = 7 or k = -4\r<BR>\n" );
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document.write( "in the equation k = (x + 3)/(x - 4), replace k with 7 and solve for x.  <BR>\n" );
document.write( "after you do that, replace k with - 4 and solve for x.\r<BR>\n" );
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document.write( "you should get x = 31/6 or x = 13/5.\r<BR>\n" );
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document.write( "it should be able to be solved the way that you showed, but i think solving for k first is probably easier.\r<BR>\n" );
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