document.write( "Question 116271: hi guys, we are really not getting how a algebraic equasion from a word
\n" ); document.write( "problem, eg
\n" ); document.write( "A woman is 6 yrs older than three times her daughters age. Their ages total
\n" ); document.write( "46. What are their ages?
\n" ); document.write( "Let x = daughter's age
\n" ); document.write( "Let 3x = mother's age
\n" ); document.write( "x + 3x=46 11.5 +3(11.5)=?46
\n" ); document.write( "4x =46
\n" ); document.write( "x 11.5 46=46
\n" ); document.write( "3x = 3(11.5)
\n" ); document.write( "3x= 34.5 woman's age 11.5 = daughter's age
\n" ); document.write( "Are we right or have we just not got it need some hints
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Algebra.Com's Answer #84564 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
Let daughter's age = x yrs.
\n" ); document.write( "Then, mother's age = (3x + 6) yrs.\r
\n" ); document.write( "\n" ); document.write( "x + (3x + 6) = 46
\n" ); document.write( "4x = 46 - 6 = 40
\n" ); document.write( "x = 40/4 =10\r
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\n" ); document.write( "\n" ); document.write( "3x+6 = 36 = mother's age; x = 10 = daughter's age\r
\n" ); document.write( "\n" ); document.write( "This is the correct answer!
\n" ); document.write( "Mother's age is (3x + 6) yrs. NOT 3x yrs.
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