document.write( "Question 1207648: Hi, can you please help me solve this problem? Thank you.
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document.write( "A surveyor wishes to find the distance between two inaccessible points A and B. As shown in the figure, two points C and D are selected from which it is possible to view both A and B. The distance CD and the angles ACD, ACB, BDC, and BDA are then measured. If CD=120~ft, ∠ACD=115°, ∠ACB=92°, ∠BDC=125°, and ∠BDA=100°, approximate the distance AB. \n" );
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Algebra.Com's Answer #845633 by math_tutor2020(3816)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Refer to the diagram tutor Edwin has drawn. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are a lot of triangles to keep track of, so it might be helpful to peel the triangles ACD and BCD apart to get this \n" ); document.write( " \n" ); document.write( "The diagrams aren't to scale.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Recall that for any triangle, the interior angles always add to 180 degrees. \n" ); document.write( "We'll use this fact to find the missing angles of triangles ACD and BCD.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For triangle ACD, the missing angle is A = 180-C-D = 180-115-25 = 40 degrees. \n" ); document.write( "For triangle BCD, the missing angle is B = 180-C-D = 180-23-125 = 32 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's update the diagram \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From here, we have a few pathways we could take. \n" ); document.write( "The path I'll take is to determine the side AC (from triangle ACD) and determine side BC (from triangle BCD). \n" ); document.write( "Use the Law of Sines to find these lengths.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll get you started with the setup equations \n" ); document.write( "AC/sin(D) = CD/sin(A) \n" ); document.write( "AC/sin(25) = 120/sin(40) \n" ); document.write( "and \n" ); document.write( "BC/sin(D) = CD/sin(B) \n" ); document.write( "BC/sin(125) = 120/sin(32) \n" ); document.write( "Make sure that your calculator is set to degrees mode.\r \n" ); document.write( "\n" ); document.write( "I'll let the student finish this subsection.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--------------------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's focus on triangle ABC. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The last batch of steps would be to use the Law of Cosines to find the length of side AB. \n" ); document.write( "x = length of AC \n" ); document.write( "y = length of BC \n" ); document.write( "z = length of AB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Law of Cosines \n" ); document.write( "z^2 = x^2 + y^2 - 2*x*y*cos(C) \n" ); document.write( "z^2 = x^2 + y^2 - 2*x*y*cos(92)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let the student finish up. \n" ); document.write( " \n" ); document.write( " |