document.write( "Question 1207629: Write each expression in the form a + bi.\r
\n" ); document.write( "\n" ); document.write( "1. 2i(i^(-3))\r
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\n" ); document.write( "\n" ); document.write( "2. 2i(i^(-3)) รท i^(-4)
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Algebra.Com's Answer #845603 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "1.\r
\n" ); document.write( "\n" ); document.write( "\"2i%28i%5E%28-3%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"2i%2Fi%5E3\"
\n" ); document.write( "=\"2%2Fi%5E2\"...........since \"i%5E2=-1\"
\n" ); document.write( "=\"2%2F-1\"
\n" ); document.write( "=\"-2\"\r
\n" ); document.write( "\n" ); document.write( " in the form \"a+%2B+bi\" \"a=-2\" and \"b=0\", so you have \r
\n" ); document.write( "\n" ); document.write( "\"-2\"\r
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\n" ); document.write( "\n" ); document.write( "2. \"2i%28i%5E%28-3%29%29%2Fi%5E%28-4%29\"....from 1. we have that \"2i%28i%5E%28-3%29%29=-2\"\r
\n" ); document.write( "\n" ); document.write( "=\"-2%2Fi%5E%28-4%29\".........\"i%5E%28-4%29=1%2Fi%5E4=1%2F%28i%5E2%29%5E2=1%2F%28-1%29%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "=\"-2%2F1\"\r
\n" ); document.write( "\n" ); document.write( "=\"-2\"\r
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