document.write( "Question 1207560: The sides of a right angled triangle are such that the sum of the length of the
\n" ); document.write( "longest and that of the shortest side is twice the length of remaining side, the
\n" ); document.write( "longest side of the triangle if the longer of the sides containing the right
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Algebra.Com's Answer #845599 by MathTherapy(10552)\"\" \"About 
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document.write( "The sides of a right angled triangle are such that the sum of the length of the\r\n" );
document.write( "longest and that of the shortest side is twice the length of remaining side, the\r\n" );
document.write( "longest side of the triangle if the longer of the sides containing the right\r\n" );
document.write( "angle is 9 CM more than half the hypotenuse is??\r\n" );
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document.write( "I agree with Sir Edwin's interpretation.\r\n" );
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document.write( "Let length of the LONGEST side (Hypotenuse) be H, the shortest side, S, and the middle side, M\r\n" );
document.write( "                                           We then get: H + S = 2M\r\n" );
document.write( "                                      But, it's given that \"matrix%281%2C3%2C+M%2C+%22=%22%2C+H%2F2+%2B+9%29\"\r\n" );
document.write( "                                So, H + S = 2M becomes:  \r\n" );
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document.write( "             We now have the lengths of all 3 sides as: \r\n" );
document.write( "As this is a right-angled triangle, we have:   \r\n" );
document.write( "                        4H2 - H2 - 36H - 1,620 = 0 ----- Multiplying by LCD, 4\r\n" );
document.write( "                             3H2 - 36H - 1,620 = 0 \r\n" );
document.write( "                             3(H2 - 12H - 540) = 3(0) \r\n" );
document.write( "                                H2 - 12H - 540 = 0 \r\n" );
document.write( "                              (H - 30)(H + 18) = 0\r\n" );
document.write( "                                        H - 30 = 0          OR        H + 18 = 0 ==> H (Hypotenuse) = - 18 (IGNORE)\r\n" );
document.write( "Length of longest side (HYPOTENUSE), or H = 30 cm
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