document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207606>Question 1207606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Really need help on this problem.\r<BR>\n" );
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document.write( "2x + 3y = 12<BR>\n" );
document.write( "x - 2y = -3\r<BR>\n" );
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document.write( "Thank you in advance.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845570 by </B><A HREF=/tutors/aboutme.mpl?userid=Timnewman><B>Timnewman(323)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Timnewman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Timnewman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's solve this system of equations using the elimination method.\r<BR>\n" );
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document.write( "First, we can multiply the two equations by necessary multiples such that the coefficients of y's in both equations are the same:\r<BR>\n" );
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document.write( "1. Multiply the first equation by 2 and the second equation by 3:\r<BR>\n" );
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document.write( "4x + 6y = 24 (Multiplying the first equation by 2)<BR>\n" );
document.write( "3x - 6y = -9 (Multiplying the second equation by 3)\r<BR>\n" );
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document.write( "1. Add both equations to eliminate y:\r<BR>\n" );
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document.write( "(4x + 6y) + (3x - 6y) = 24 + (-9)<BR>\n" );
document.write( "4x + 3x = 15<BR>\n" );
document.write( "7x = 15\r<BR>\n" );
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document.write( "1. Divide by 7:\r<BR>\n" );
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document.write( "x = 15/7\r<BR>\n" );
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document.write( "1. Substitute the value of x into one of the original equations to find the value of y:\r<BR>\n" );
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document.write( "2x + 3y = 12<BR>\n" );
document.write( "2(15/7) + 3y = 12\r<BR>\n" );
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document.write( "1. Solve for y:\r<BR>\n" );
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document.write( "3y = 12 - 30/7<BR>\n" );
document.write( "3y = (84 - 30)/7<BR>\n" );
document.write( "3y = 54/7<BR>\n" );
document.write( "y = 18/7\r<BR>\n" );
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document.write( "So, the solution to the system is x = 15/7 and y = 18/7. </SPAN>\n" );
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