document.write( "Question 1207588: Jarome has $880 in ten and twenty dollar bills. If he has 48 bills in total, how many of each bill does he have? \n" ); document.write( "
Algebra.Com's Answer #845553 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If the speed of getting the answer is important and formal algebra is not required -- e.g., in a timed competitive math contest -- here is a quick and easy way to solve this kind of problem using logical reasoning and simple mental arithmetic. \n" ); document.write( "If all 48 bills were $10 bills, the total would be $480. \n" ); document.write( "The actual total is $880, which is $400 more than $480. \n" ); document.write( "Each $20 bill is worth $10 more than each $10 bill. The number of $20 bills needed to make the additional $400 is 400/10 = 40. \n" ); document.write( "ANSWER: 40 $20 bills; 48-40 = 8 $10 bills \n" ); document.write( "NOTE: Even if the problem required a formal algebraic solution, solving problems using logical reasoning and mental arithmetic is excellent brain exercise. \n" ); document.write( " \n" ); document.write( " |