document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207572>Question 1207572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "Tim Sam and Xavier received some red packets. The total number of red packets sam and Xavier had is 3 times what tim had. The ratio of red packets sam had to Xavier was 3:7. If Tim and Xavier had 155 red packets together how many did Tim have.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845524 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is what i get.\r<BR>\n" );
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document.write( "let T = the amount that tim had, S = the amount that sam had, X = the amount that  xavier had.\r<BR>\n" );
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document.write( "you are given that:\r<BR>\n" );
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document.write( "S + X = 3T<BR>\n" );
document.write( "S / X = 3 / 7<BR>\n" );
document.write( "T + X = 155\r<BR>\n" );
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document.write( "from S / X = 3 / 7, solve for S to get S = 3X / 7\r<BR>\n" );
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document.write( "S + X = 3T becomes 3X / 7 + X = 3T<BR>\n" );
document.write( "multiply both sides of this equation by 7 to get:<BR>\n" );
document.write( "3X + 7X = 21T<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "10X = 21T<BR>\n" );
document.write( "solve for X to get:<BR>\n" );
document.write( "X = 2.1T\r<BR>\n" );
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document.write( "T + X = 155 becomes T + 2.1T = 155 which becomes 3.1T = 155.<BR>\n" );
document.write( "solve for T to get T = 50<BR>\n" );
document.write( "solve for X to get X = 105\r<BR>\n" );
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document.write( "from S = 3X / 7, solve for S to get S = (3 * 105) / 7 = 45.\r<BR>\n" );
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document.write( "you now have:<BR>\n" );
document.write( "T = 50<BR>\n" );
document.write( "X = 105<BR>\n" );
document.write( "S = 45\r<BR>\n" );
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document.write( "confirm as correct because ......\r<BR>\n" );
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document.write( "S + X = 3T becomes 45 + 105 = 150 = 3 * 50.<BR>\n" );
document.write( "S / X = 3 / 7 becomes 45 / 105 = 3 / 7 when you divide both numerator and divisor by 15.<BR>\n" );
document.write( "T + X = 155 becomes 50 + 105 = 155.\r<BR>\n" );
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document.write( "everything checks out.\r<BR>\n" );
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document.write( "your solution is T = 50. </SPAN>\n" );
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