document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207548>Question 1207548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A drip of hot water each second wastes g gallons.  Determine amount (gal.) wa<BR>\n" );
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document.write( "A drip is approx .33 ml.\r<BR>\n" );
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document.write( "Not sure how to solve. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845481 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use a 30 day month<BR>\n" );
document.write( "0.33 ml/drip*1 drip/second*86400 sec/day*30 days/month. Note the units at the end are ml/month<BR>\n" );
document.write( "=855360 ml/month.<BR>\n" );
document.write( "Now we want gal/month. so the units for the next part must be gal/ml<BR>\n" );
document.write( "1 liter=0.264 gallons<BR>\n" );
document.write( "1 ml is 0.0002264 gallons<BR>\n" );
document.write( "1=0.000264 gal/ml<BR>\n" );
document.write( "therefore, multiplying that by 855360, we get 225.82 gallons. This is the answer.<BR>\n" );
document.write( "for sec in a day 60se/1 min*60 min/1 hr*24 hr/1 day=86400 sec/day\r<BR>\n" );
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document.write( "Check<BR>\n" );
document.write( "855360 ml=855.360 liters  and that *2.2 lb/liter=1881 lb.<BR>\n" );
document.write( "one gallon is about 8.3 pounds<BR>\n" );
document.write( "so 1881 lb./8.3 lb./gal units will be gal.=226.72. this is consistent with the above considering I rounded the 2.2 lb/liter and the 8.3 pounds per gallon. </SPAN>\n" );
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