document.write( "Question 1207535: Hi
\n" ); document.write( "A container can hold either 60 small boxes or 48 big boxes. If there are already 20 small and 24 big boxes in the container how many more big boxes can the container still hold.
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Algebra.Com's Answer #845472 by ikleyn(52781)\"\" \"About 
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A container can hold either 60 small boxes or 48 big boxes.
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document.write( "\"20%2F60\" = \"1%2F3\".  Hence, 1/3 of the container volume is just occupied by the 20 small boxes.\r\n" );
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document.write( "\"24%2F48\" = \"1%2F2\".  Hence, 1/2 of the container volume is just occupied by the 24 big boxes.\r\n" );
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document.write( "Taking the sum, we see that 1/3 + 1/2 = 5/6 of the container volume is just occupied\r\n" );
document.write( "by the 20 small and 24 big boxes; 1/6 of the container volume still remains free.\r\n" );
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document.write( "So, \"%28%281%2F6%29%29%2F%28%281%2F48%29%29\" = \"48%2F6\" = 8 big boxes can be added to occupy free space.   ANSWER\r\n" );
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