document.write( "Question 1207523: show that 2x ^ 2 + 3y^2 - x + 2y + 1 = 0 is a circle \n" ); document.write( "
Algebra.Com's Answer #845446 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "a circle formula is\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2+%2B%28y-k%29%5E2=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "so, complete squares in given equation\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+%2B+3y%5E2+-+x+%2B+2y+%2B+1+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%282x%5E2-x%29+%2B+%283y%5E2+%2B+2y%29++=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2-x%2F2%29%2B3%28y%5E2%2B2y%2F3%29=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2-%281%2F2%29x%2Bb%5E2%29-2b%5E2%2B3%28y%5E2%2B%282%2F3%29y%2Bb%5E2%29-3b%5E2=-1\"\r
\n" ); document.write( "\n" ); document.write( "for \"x+\"part \"b=%281%2F2%29%2F2=1%2F4\"\r
\n" ); document.write( "\n" ); document.write( "for \"y\" part \"b=%282%2F3%29%2F2=1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x-1%2F4%29%5E2-2%281%2F16%29%2B3%28y%2B1%2F3%29%5E2-3%281%2F9%29=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x-1%2F4%29%5E2-1%2F8%2B3%28y%2B1%2F3%29%5E2-1%2F3=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x-1%2F4%29%5E2%2B3%28y%2B1%2F3%29%5E2=-1%2B1%2F8%2B1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28x-1%2F4%29%5E2%2B3%28y%2B1%2F3%29%5E2=-13%2F24\"\r
\n" ); document.write( "\n" ); document.write( "as you can see, we cannot get a formula of a circle which means given equation is NOT a circle\r
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