document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116265>Question 116265</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by graphing: x^2+y^2=25 and x-2y=-5\r<BR>\n" );
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document.write( "I graphed my circle and line perfectly<BR>\n" );
document.write( "but when it came to using either addition or substitution methods<BR>\n" );
document.write( "to find the solution set (where the line crosses the circle at two points)<BR>\n" );
document.write( "I had problems:(\r<BR>\n" );
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document.write( "I can see by looking at my graph that one solution is (-5,0) and the other<BR>\n" );
document.write( "is approximately (3.5, 4.5) but I have to use one of the above methods <BR>\n" );
document.write( "to show how I came up with my solutions and show my work.\r<BR>\n" );
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document.write( "This is what I've done so far:<BR>\n" );
document.write( "Using substitution method\r<BR>\n" );
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document.write( "x^2+y^2=25   and   x-2y=-5  (changed to x=2y-5) and substituted in to 1st equation<BR>\n" );
document.write( "(2y-5)^2+y^2=25<BR>\n" );
document.write( "4y^2-20y+25+y^2=25<BR>\n" );
document.write( "(combine like terms)<BR>\n" );
document.write( "5y^2-20y+25=25<BR>\n" );
document.write( "(subtract 25 from each side)<BR>\n" );
document.write( "5y^2-20y=0\r<BR>\n" );
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document.write( "This is where I loose it, because in class all of our problems worked out nice and neat<BR>\n" );
document.write( "and all I had to do was factor my quadratic equation to come up with one solution and<BR>\n" );
document.write( "then plug that into one of my original problems to get my second.<BR>\n" );
document.write( " <BR>\n" );
document.write( "No one in study group tonight quite got this one either and this is due this Thursday! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84543 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+y^2=25 <BR>\n" );
document.write( "x-2y=-5 <BR>\n" );
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document.write( "x = 2y-5<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "(2y-5)^2 + y^2 = 25<BR>\n" );
document.write( "4y^2-20y+25 + y^2 = 25<BR>\n" );
document.write( "5y^2-20y=0<BR>\n" );
document.write( "5y(y-4) = 0<BR>\n" );
document.write( "y = 0 or y = 4<BR>\n" );
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document.write( "Substitute y = 0 into x-2y=-5 to get x=-5<BR>\n" );
document.write( "Substitute y = 4 into x-2y=-5 to get x-8 = -5; x = 3<BR>\n" );
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document.write( "Solution: (-5,0) and (3,4)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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