document.write( "Question 1207493: A vehicle of mass 1325 kg and a co efficient of a friction between the grounds/tires is 0.4. what is the maximum retarding force which can be used to stop it without skidding \n" ); document.write( "
Algebra.Com's Answer #845423 by Edwin McCravy(20060)\"\" \"About 
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document.write( "To find the maximum retarding force that can be used to stop the vehicle \r\n" );
document.write( "without skidding:\r\n" );
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document.write( "Maximum retarding force = Coefficient of friction x Normal force\r\n" );
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document.write( "The normal force is the force exerted by the ground on the vehicle, which is\r\n" );
document.write( "equal to the weight of the vehicle.\r\n" );
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document.write( "Weight of the vehicle = Mass x Acceleration due to gravity\r\n" );
document.write( "Weight of the vehicle = 1325 kg x 9.8 m/s2 = 12997.5 N\r\n" );
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document.write( "Now, we can calculate the maximum retarding force:\r\n" );
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document.write( "Maximum retarding force = Coefficient of friction x Normal force\r\n" );
document.write( "Maximum retarding force = 0.4 x 12997.5 N = 5199 N\r\n" );
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document.write( "Therefore, the maximum retarding force that can be used to stop the vehicle\r\n" );
document.write( "without skidding is 5199 N.\r\n" );
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document.write( "Edwin
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