document.write( "Question 1207490: $5^{(}logx-1)/125=(1/5)^{(}logx)^{2}-logx$ \n" ); document.write( "

Algebra.Com's Answer #845411 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "     =  \r\n" );
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document.write( "Write right part with the base 5\r\n" );
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document.write( "     =  \r\n" );
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document.write( "Simplify left side\r\n" );
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document.write( "     = .\r\n" );
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document.write( "Since the bases are equal, it implies that the indexes are equal, too\r\n" );
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document.write( "    log(x)-4 = log(x) - (log(x))^2\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "     -4 = -(log(x))^2\r\n" );
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document.write( "      4 = (log(x))^2\r\n" );
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document.write( "Take square root of both sides\r\n" );
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document.write( "      log(x) = +/- \r\n" );
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document.write( "      log(x) = +/- 2\r\n" );
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document.write( "There are two solutions:  x=  = 100  and  x=  = 0.01.    ANSWER\r\n" );
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