document.write( "Question 1207491: The cost function for a certain company is
\n" ); document.write( "C = 40x + 800
\n" ); document.write( " and the revenue is given by
\n" ); document.write( "R = 100x − 0.5x2.
\n" ); document.write( " Recall that profit is revenue minus cost. Set up a quadratic equation and find two values of x (production level) that will create a profit of $800.
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Algebra.Com's Answer #845401 by MathLover1(20849)\"\" \"About 
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\"C+=+40x+%2B+800\"\r
\n" ); document.write( "\n" ); document.write( "and the revenue is given by\r
\n" ); document.write( "\n" ); document.write( "\"R+=+100x+-0.5x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Recall that profit is revenue minus cost.\r
\n" ); document.write( "\n" ); document.write( "\"P=R-C\"\r
\n" ); document.write( "\n" ); document.write( "\"P=100x+-0.5x%5E2-%2840x+%2B+800%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=100x-0.5x%5E2-40x+-+800\"\r
\n" ); document.write( "\n" ); document.write( "\"P=+-+0.5x%5E2%2B60x+-+800\"\r
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\n" ); document.write( "\n" ); document.write( " two values of \"x+\"(production level) that will create a profit of $\"800\":\r
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\n" ); document.write( "\n" ); document.write( "\"800=+-0.5x%5E2%2B60x+-+800\"\r
\n" ); document.write( "\n" ); document.write( "\"800%2B0.5x%5E2-60x+%2B+800=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5x%5E2-60x+%2B+1600=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28x%5E2-120x%2B3200%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5%28x%5E2-40x-80x%2B3200%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0.5+%28x+-+80%29+%28x+-+40%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"x=40\"\r
\n" ); document.write( "\n" ); document.write( "\"x=80\"\r
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