document.write( "Question 1207394: Sofia has 45 markers and 60 crayons that she wants to put into
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document.write( "boxes.
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document.write( "• All the boxes will have an equal number of markers.
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document.write( "• All the boxes will have an equal number of crayons.
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document.write( "What is the greatest number of boxes Sofia can make using all
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document.write( "the markers and crayons? \n" );
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Algebra.Com's Answer #845396 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "Let M = the number of markers in each a box\r\n" ); document.write( "Let C = the number of crayons in each a box\r\n" ); document.write( "Let N = the number of boxes.\r\n" ); document.write( "\r\n" ); document.write( "So N(M+C) must equal the total number of markers and crayons.\r\n" ); document.write( "N(M+C) = NM + NC = 45 + 60, so N must be a factor of both 45 and 60 \r\n" ); document.write( "\r\n" ); document.write( "For N to be as large as possible, it must be the greatest common factor\r\n" ); document.write( "of 45 and 60, which is 15. \r\n" ); document.write( "\r\n" ); document.write( "N(M+C) = 15M + 15C and 15M=45 and 15C=60, or M=3 and C=4 \r\n" ); document.write( "\r\n" ); document.write( "So there are 15 boxes, with 3 markers and 4 crayons in each box.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |