document.write( "Question 1207481: Linda Smaoke invests a total of $10,000 in two savings accounts. One account pays 6% interest, and the other,7%. Find the amount placed in each account if the accounts receive a total of $660 in interest after 1 year. \n" ); document.write( "
Algebra.Com's Answer #845383 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is a quick and easy non-algebraic method for solving any 2-part \"mixture\" problem like this. \n" ); document.write( "$10,000 all invested at 6% would yield $600 interest; all at 7% would yield $700 interest. \n" ); document.write( "Use any arithmetic method you want (perhaps a number line) to observe/calculate that $660 is 60/100 = 3/5 of the way from $600 to $700. \n" ); document.write( "That means 3/5 of the total was invested at the higher rate. \n" ); document.write( "3/5 of $10,000 is $6000. \n" ); document.write( "ANSWER: $6000 was invested at 7%, the other $4000 at 6% \n" ); document.write( "CHECK: .07($6000)+.06($4000) = $420+$240 = $660 \n" ); document.write( " \n" ); document.write( " |