document.write( "Question 1207482: Write each expression in the standard form a+bi.\r
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\n" ); document.write( "\n" ); document.write( "How do I simplify i^n when n is a big number?\r
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\n" ); document.write( "\n" ); document.write( "Two samples:\r
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\n" ); document.write( "\n" ); document.write( "A. i^14\r
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\n" ); document.write( "\n" ); document.write( "B. 2i^(8)(2 + i^4)\r
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Algebra.Com's Answer #845377 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "When dealing with large numbers, try to look at small examples to see if a pattern can be formed.\r
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\n" ); document.write( "\n" ); document.write( "We'll look at the first few powers of i
\n" ); document.write( "i^0 = 1
\n" ); document.write( "i^1 = i
\n" ); document.write( "i^2 = ( sqrt(-1) )^2 = -1
\n" ); document.write( "i^3 = i*i^2 = i*(-1) = -i
\n" ); document.write( "i^4 = ( i^2 )^2 = (-1)^2 = 1
\n" ); document.write( "i^5 = i*i^4 = i*1 = i
\n" ); document.write( "Etc\r
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\n" ); document.write( "\n" ); document.write( "The summarized list would be
\n" ); document.write( "i^0 = 1
\n" ); document.write( "i^1 = i
\n" ); document.write( "i^2 = -1
\n" ); document.write( "i^3 = -i
\n" ); document.write( "i^4 = 1
\n" ); document.write( "i^5 = i
\n" ); document.write( "Etc\r
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\n" ); document.write( "\n" ); document.write( "Be sure not to mix up the lowercase \"eye\" with the numeric digit \"one\".
\n" ); document.write( "The two symbols unfortunately look similar at a quick glance.\r
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\n" ); document.write( "\n" ); document.write( "Anyways, the pattern we found was: 1, i, -1, -i, 1, i, ...
\n" ); document.write( "As you can see, once reaching 1, the pattern starts over again.
\n" ); document.write( "Therefore, this sequence repeats itself every 4 elements.\r
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\n" ); document.write( "\n" ); document.write( "Why is this useful? Because we can divide the large-ish exponent of 14 by 4 to determine the remainder.
\n" ); document.write( "14/4 = 3 remainder 2
\n" ); document.write( "The \"remainder 2\" leads us to i^2 since it has exponent of 2.
\n" ); document.write( "Ignore the quotient. We only care about the remainder.\r
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\n" ); document.write( "\n" ); document.write( "i^14 = i^2 = -1 which is the answer to part A.\r
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\n" ); document.write( "\n" ); document.write( "Another example:
\n" ); document.write( "i^15 = i^3 = -i
\n" ); document.write( "since 15/4 gives some quotient with remainder 3\r
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\n" ); document.write( "\n" ); document.write( "Another example:
\n" ); document.write( "i^98 = i^2 = -1
\n" ); document.write( "since 98/4 yields remainder 2.\r
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\n" ); document.write( "\n" ); document.write( "If in doubt, turn to something like WolframAlpha to help confirm the answer
\n" ); document.write( "https://www.wolframalpha.com/input/?i=i%5E14
\n" ); document.write( "I use this tool a lot. Another tool that I use often is GeoGebra.
\n" ); document.write( "There are many other similar tools on the web which I encourage you to explore your favorite.\r
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\n" ); document.write( "\n" ); document.write( "I'll leave part B for the student to handle.
\n" ); document.write( "If you are still stuck, or have any questions, then please let me know.
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