document.write( "Question 1207481: Linda Smaoke invests a total of $10,000 in two savings accounts. One account pays 6% ​interest, and the​ other,7%. Find the amount placed in each account if the accounts receive a total of $660 in interest after 1 year. \n" ); document.write( "
Algebra.Com's Answer #845375 by Msexcel (1)\"\" \"About 
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\n" ); document.write( "x + y = 10000
\n" ); document.write( ".06x + .07y = 660\r
\n" ); document.write( "\n" ); document.write( "From equation (1)
\n" ); document.write( "x = 10,000 - y\r
\n" ); document.write( "\n" ); document.write( "Substitute into (2)
\n" ); document.write( ".06x + .07y = 660\r
\n" ); document.write( "\n" ); document.write( ".06(10,000 - y) + .07y = 660\r
\n" ); document.write( "\n" ); document.write( "600 - .06y + .07y = 660\r
\n" ); document.write( "\n" ); document.write( "- .06y + .07y = 660 - 600\r
\n" ); document.write( "\n" ); document.write( ".01y = 60\r
\n" ); document.write( "\n" ); document.write( "y = 60/.01\r
\n" ); document.write( "\n" ); document.write( "y = 600\r
\n" ); document.write( "\n" ); document.write( "Substitute the value of y into equation (1)
\n" ); document.write( "x + y = 10,000
\n" ); document.write( "x + 600 = 10,000
\n" ); document.write( "x = 10,000 - 600
\n" ); document.write( "x = 9400\r
\n" ); document.write( "\n" ); document.write( "Therefore, $9,400 was placed in the account which pays 6% interest rate and $600 was placed in the account which pays 7% interest rate
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