document.write( "Question 253049: If x is a positive integer, which of the following CANNOT be an integer?\r
\n" ); document.write( "\n" ); document.write( "(A) \"+sqrt%28x-1%29+\" (B) \"sqrt%28x%5E2+-+1%29\" (C) \"+%28x%2B4%29+%2F+%28x-2%29+\" (D) \"+%28x%2B4%29+%2F+%28x%2B2%29+\" (E) \"+5%2F%28x%2B1%29+\"
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Algebra.Com's Answer #845347 by comfuse(1)\"\" \"About 
You can put this solution on YOUR website!
The answer is D.\r
\n" ); document.write( "\n" ); document.write( "For \"+x=0+\" , the function evaluates to 2. Furthermore, since the function is strictly decreasing as \"+x+\" increases (its derivative is negative for all \"+x+%3E+0+\" ), all positive values evaluate to strictly less than 2. Lastly, the fraction has a vertical asymptote of \"+y+=+1+\" (the ratio of the leading coefficients of numerator and denominator), which means the expression is also strictly larger than 1.
\n" ); document.write( "In conclusion, for all positive integers, the function always evaluates to strictly less than 2 and strictly larger than 1, hence, never an integer.\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+300%2C+-10%2C+100%2C+-1%2C+3%2C+%28x%2B4%29%2F%28x%2B2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "Answer B is not correct, as for \"+x+=+1+\" it evaluates to 0, which is an integer.
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