document.write( "Question 1207452: \"+2x=sqrt%288-4x%29+\" \n" ); document.write( "
Algebra.Com's Answer #845324 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "As the other tutor mentions, the only solution is x = 1.\r
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\n" ); document.write( "\n" ); document.write( "The other value x = -2 is extraneous. \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph mentioned.
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2x%2C+sqrt%288-4x%29%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Let's reflect the square root curve over the x axis to handle \"y+=+-sqrt%288-4x%29\"
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2x%2C+sqrt%288-4x%29%2C-sqrt%288-4x%29%29+\"
\n" ); document.write( "Notice the new intersection point (-2,-4) which is the intersection of y = 2x and y = -sqrt(8-4x)\r
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\n" ); document.write( "\n" ); document.write( "So if we were allowed to plot the plus minus of \"sqrt%288-4x%29\" then we'd get two solutions for x.
\n" ); document.write( "However, we only plot the positive version.
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