document.write( "Question 1207432: Kara surveyed 200 people, chosen at random on thompson drive, to try to determine what % of thompsonites are skiers. 86 people in her sample said they were skiers. \r
\n" ); document.write( "\n" ); document.write( "A.) What is the 95% confidence interval for the percent of Thompsonites who are skiers ? (Formula: 95% confidence interval = mean ± 1.96(standard deviation)
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\n" ); document.write( "B.) Calculate the margin of error.
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Algebra.Com's Answer #845300 by Theo(13342)\"\" \"About 
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sample size is 200
\n" ); document.write( "p = 86/200 = .43.
\n" ); document.write( "q = (1 - 86/200) = 114/200 = .57.
\n" ); document.write( "s = sqrt(.43 * .57 / 200) = .035007 rounded to 6 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "critical z-score at 95% confidence interval is z = plus or minus 1.96.\r
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\n" ); document.write( "\n" ); document.write( "z-score formula is z = (x-m)/s\r
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\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the critical raw score.
\n" ); document.write( "m is the raw mean which is equal to p.
\n" ); document.write( "s is the standard error which is equal to s.\r
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\n" ); document.write( "\n" ); document.write( "on the high side of the confidence interval, the formula becomes 1.96 = (x - .43) / .035007.
\n" ); document.write( "solve for x to get x = 1.96 * .035007 + .43 = .49861372.\r
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\n" ); document.write( "\n" ); document.write( "on the low side of the confidence interval, the formula becomes -1.906 = (x - .43) / .035007.
\n" ); document.write( "solve for x to get x = -1.96 * .035007 + .43 = .36138628.\r
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\n" ); document.write( "\n" ); document.write( "the 95% confidence interval is .36138628 to .49861372.\r
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\n" ); document.write( "\n" ); document.write( "the margin of error is (.49861372 minus .36138628) / 2 = .06861375.\r
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