document.write( "Question 1207440: a. Draw 4 different rectangles, all of which have an area of 4 square inches. Label your rectangles with their lengths and widths.(Think about decimals and fractions)
\n" ); document.write( "b. Determine the permiters of each of your rectangles in part (a). Then label your rectangles A,B,C,and D in increasing order of their perimeters, so that A has the smallest perimeter and D has the largest permiter among your rectangles.
\n" ); document.write( "c. Qualitatively, how do the smallesr-perimeter rectangles that you drew in part (a)look different from the larger-perimeter rectangles? Describe how the shapes of the rectangles change as you go from the rectangle of the smallest perimeter to the rectangle of the largest perimeter. \n" ); document.write( "
Algebra.Com's Answer #845293 by Edwin McCravy(20054)\"\" \"About 
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document.write( "Rectangle A has length 2.5, width 4/2.5 = 1.6, perimeter 2(2.5)+2(1.6)=8.2\r\n" );
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document.write( "Rectangle B has length 3.2, width 4/3.2 = 1.25, perimeter 2(3.2)+2(1.25)=8.9\r\n" );
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document.write( "Rectangle C has length 4, width 4/4 = 1, perimeter 2(4)+2(1)=10\r\n" );
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document.write( "Rectangle D has length 5, width 4/5 = 0.8, perimeter 2(5)+2(0.8)=11.6\r\n" );
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document.write( "So for given area 4, we might conjecture that rectangles with smaller perimeters\r\n" );
document.write( "have their lengths closer to their widths.  And therefore, rectangles with\r\n" );
document.write( "larger perimeters have their lengths much greater than their widths.\r\n" );
document.write( "The nearer the rectangles are to a square, the smaller their perimeter.\r\n" );
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document.write( "So we might make a more general conjecture that of all rectangles that have a\r\n" );
document.write( "given area, the one with the smallest perimeter possible is the one when the\r\n" );
document.write( "rectangle is a square.\r\n" );
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document.write( "Edwin
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