document.write( "Question 1207406: Use the discriminant to determine whether each quadratic equation has two unequal real solutions,a repeated real solution,or no real solution,without solving the equation.\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 4x + 7 = 0\r
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\n" ); document.write( "\n" ); document.write( "I know the discriminant is the radicand of the quadratic formula.\r
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\n" ); document.write( "\n" ); document.write( "So, I need to use b^2 - 4ac where a = 1, b = 4 and c = 7.\r
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\n" ); document.write( "\n" ); document.write( "b^2 - 4ac\r
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\n" ); document.write( "\n" ); document.write( "(4)^2 - 4(1)(7)\r
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\n" ); document.write( "\n" ); document.write( "16 - 28 = -12\r
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\n" ); document.write( "\n" ); document.write( "The answer is -12.\r
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\n" ); document.write( "\n" ); document.write( "The discriminant is negative, which means the equation has no real solution.\r
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\n" ); document.write( "\n" ); document.write( "You say? \r
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\n" ); document.write( "\n" ); document.write( "What would be an example of a repeated real solution or no solution at all? \r
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Algebra.Com's Answer #845265 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Note it is possible, or even probable, that you have not asked the second question correctly.

\n" ); document.write( "As implied in the statement of the problem, every quadratic equation has two unequal real solutions, a repeated real solution, or no real solutions. There is no quadratic equation that has \"no solution at all\".

\n" ); document.write( "The given equation has no real solutions: b^2-4ac = 16-28 = -12 < 0.

\n" ); document.write( "By definition, any perfect square quadratic polynomial has a repeated real solution (or, better stated, two equal solutions): x^2-6x+9 --> b^2-4ac = 36-36 = 0.

\n" ); document.write( "For an example with two real solutions, start with any quadratic polynomial that is a factor of two linear polynomials. Example: (x+3)(x-2) = x^2+x-6 --> b^2-4ac = 1+24 = 25 > 0.

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