document.write( "Question 1207400: Kenneth's father is 36 years older than he is. In 7 years' time, his father will be double Kenneth's age. How old is Kenneth's father now? \n" ); document.write( "
Algebra.Com's Answer #845249 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A formal algebraic solution....

\n" ); document.write( "Let x be the age of Kenneth's father
\n" ); document.write( "Then x-36 is Kenneth's age

\n" ); document.write( "x+7 = father's age in 7 years
\n" ); document.write( "(x-36)+7 = x-29 = Kenneth's age in 7 years

\n" ); document.write( "In 7 years, the father's age will be twice Kenneth's age:

\n" ); document.write( "x+7=2(x-29)
\n" ); document.write( "x+7=2x-58
\n" ); document.write( "65=x

\n" ); document.write( "ANSWER: 65

\n" ); document.write( "CHECK: x+7=65+7=72; x-29=65-29=36; 72=2*36

\n" ); document.write( "Informally (using logical reasoning and simple mental arithmetic, which is good exercise)....

\n" ); document.write( "The difference in their ages is 36; when the father is twice as old, their ages will be 72 and 36. That will be 7 years from now, so the father's age now is 72-7 = 65
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