document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207380>Question 1207380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Computing Hourly Wages Leigh is paid time-and-a-half for hours worked in excess of 40 hours and double-time for hours worked on Sunday.If Leigh had gross weekly wages of $456 for working 50 hours,4 of which were on Sunday, what is her regular hourly rate?\r<BR>\n" );
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document.write( "Let me see.\r<BR>\n" );
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document.write( "Let x = regular hourly rate\r<BR>\n" );
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document.write( "40x = 40 hours times x.\r<BR>\n" );
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document.write( "Leigh worked 10 additional hours beyond 40.\r<BR>\n" );
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document.write( "Leigh makes 1.2 for hours over 40 and double time on Sunday.\r<BR>\n" );
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document.write( "6(1.2x) = time and a half for 6 hours.\r<BR>\n" );
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document.write( "4(2x) = double time for 4 hours on Sunday.\r<BR>\n" );
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document.write( "Here is my equation set up:\r<BR>\n" );
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document.write( "40x + 6(1.2x) + 4(2x) = 456\r<BR>\n" );
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document.write( "You say?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845226 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52776)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
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document.write( "Your setup is INCORRECT.\r\n" );
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document.write( "A correct setup equation is\r\n" );
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document.write( "    40x + 6*(1.5x) + 4*(2x) = 456.\r\n" );
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document.write( "<U>Comment from student</U>: I made a typo. My 6(1.2x) should be 6(1.5x). Everything else is correct.\r<BR>\n" );
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document.write( "<U>My response</U>: A correct answer from your side should sound like THIS:\r<BR>\n" );
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document.write( "    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Thanks for your response and thanks for detecting/pointing my typo.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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