document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207345>Question 1207345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance. S metres, in which a car can stop is related to its speed, 'km/h by\r<BR>\n" );
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document.write( "S=pV+ qt² where p and q are constants. A car travelling at 10 km/h can stop in a distance to the second house is 10: 15 respectively. It is estimated that in 6 years, the value of the first house will increase by 35% and that of the second house will increase by $30,825.00. If the new ratio is 3: 4, find the original value of the first house of 5 metres and at 20 km/h in a distance of 12 metres. Calculate the distance in which a car travelling at 30 km/h can stop </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845170 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52798)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "The distance. S metres, in which a car can stop is related to its speed, 'km/h by\r<BR>\n" );
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document.write( "S=pV+ qt² where p and q are constants. A car travelling at 10 km/h can stop in a distance to the second house is 10: 15 respectively. It is estimated that in 6 years, the value of the first house will increase by 35% and that of the second house will increase by $30,825.00. If the new ratio is 3: 4, find the original value of the first house of 5 metres and at 20 km/h in a distance of 12 metres. Calculate the distance in which a car travelling at 30 km/h can stop<BR>\n" );
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document.write( "Soup of words, &nbsp;or, &nbsp;in other terms, &nbsp;simply &nbsp;GIBBERISH.\r<BR>\n" );
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document.write( "The pieces of two different problems are mixed in one post.\r<BR>\n" );
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document.write( "Throw it to the closest garbage bin.\r<BR>\n" );
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