document.write( "Question 1207335: Hi
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document.write( "Mark bought a number of pens at an average cost of $2.50 He bought another pen for $8.50 and the average cost of the pens became $4.50. How many pens did he buy altogether.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #845158 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is a very unorthodox method for solving a problem like this.... A bit difficult to learn; but if you can learn it, it is much faster than the formal algebraic solution method. Of course, if a formal algebraic solution is needed, this won't help you. \n" ); document.write( "We can treat this as a \"mixture\" problem -- we are \"mixing\" pens that cost $2.50 each with pens that cost $8.50 each to get a \"mixture\" of pens that cost an average of $4.50 each. \n" ); document.write( "For an unorthodox method for solving that problem, look at the three numbers 2.50, 4.50, and 8.50 (on a number line, if it helps) and observe/calculate that 4.50 is 1/3 of the way from 2.50 to 8.50 (from 2.50 to 8.50 is a difference of 6; from 2.50 to 4.50 is a difference of 2; 2/6 = 1/3). \n" ); document.write( "That means 1/3 of the pens were the more expensive ones. Then, since there was one $8.50 pen, the total number of pens was 3. \n" ); document.write( "ANSWER: 3 pens (1 at $8.50 and 2 at $2.50 each) \n" ); document.write( "CHECK: \n" ); document.write( "$8.50 + 2($2.50) = $13.50 \n" ); document.write( "3($4.50) = $13.50 \n" ); document.write( " \n" ); document.write( " |