document.write( "Question 1207322: f (x) is polynomial function, f '(x) + int f (x) dx = x ^4 + 13 x ^2 + 2. Find f (x) \n" ); document.write( "
Algebra.Com's Answer #845132 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "f (x) is  \"highlight%28highlight%28a%29%29\"  polynomial function, f '(x) + int f (x) dx = x ^4 + 13 x ^2 + 2,
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document.write( "We want to find f(x) as a polynomial  f(x) = \"a%5B0%5D%2Ax%5En\" + \"a%5B1%5D%2Ax%5E%28n-1%29\" + . . . + \"a%5Bn%5D\".\r\n" );
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document.write( "Taking derivative decreases the degree of a polynomial by one unit.\r\n" );
document.write( "Taking antiderivative increases the degree of a polynomial by one unit.\r\n" );
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document.write( "Since the sum   f ' (x) + int f (x) dx   is a polynomial of degree 4,\r\n" );
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document.write( "it means that the sough polynomial f(x) is of degree 3:\r\n" );
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document.write( "    f(x) = ax^3 + bx^2 + cx + d.\r\n" );
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document.write( "Then \r\n" );
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document.write( "    f ' (x)     =                        \"3a%2Ax%5E2\" + 2bx + c,\r\n" );
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document.write( "    int f(x) dx =  \"%28a%2F4%29x%5E4\" + \"%28b%2F3%29x%5E3\" + \"%28c%2F2%29x%5E2\" + dx  + E.\r\n" );
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document.write( "So, in the sum   f ' (x) + int f(x) dx\r\n" );
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document.write( "    (a)  coefficient at  \"x%5E4\"  is  \"a%2F4\"  It gives an equation\r\n" );
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document.write( "             \"a%2F4\" = 1;   hence  a = 4.\r\n" );
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document.write( "    (b)  coefficient at  \"x%5E3\"  is  0.  It gives an equation\r\n" );
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document.write( "             \"b%2F3\" = 0;   hence  b = 0.\r\n" );
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document.write( "    (c)  coefficient at  \"x%5E2\"  is  13.  It gives an equation\r\n" );
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document.write( "             \"3a%2B+c%2F2\" = 13,  or  \"3%2A4+%2B+c%2F2\" = 13  ---> \"c%2F2\" = 13 - 12 = 1  --->  c = 2.\r\n" );
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document.write( "    (d)  coefficient at  \"x\"  is  0.  It gives an equation\r\n" );
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document.write( "             2b + d = 0,  which implies  2*0 + d = 0;  hence,  d = 0.\r\n" );
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document.write( "    +------------------------------------------------------------+\r\n" );
document.write( "    |    At this point, the problem is just solved to the end.   |\r\n" );
document.write( "    |            a = 4;  b = 0;  c = 2;  d = 0.                  |\r\n" );
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document.write( "The sough polynomial is  f(x) = 4x^3 + 2x.     ANSWER\r\n" );
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document.write( "CHECK.  The derivative is f ' (x) = \"12x%5E2+%2B+2\".\r\n" );
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document.write( "        The anti-derivative is  F(x) =  \"%284%2F4%29x%5E4+%2B+%282%2F2%29x%5E2\" = \"x%5E4+%2B+x%5E2\".\r\n" );
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document.write( "        The sum f ' (x) + F(x) = \"%2812x%5E2%2B2%29\" + \"%28x%5E4+%2B+x%5E2%29\" = \"x%5E4+%2B+13x%5E2+%2B+2\".   ! correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "Do not accept any other  \"highlight%28different%29\"  answer.\r
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\n" ); document.write( "\n" ); document.write( "The solution by  Edwin is  INCORRECT.\r
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\n" ); document.write( "\n" ); document.write( "To make sure that it is incorrect,  simply take the antiderivative of his leading term  \"%28-1%2F3%29x%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "This antiderivative is  \"%28-1%2F%283%2A4%29%29%2Ax%5E4\" = \"%28-1%2F12%29x%5E4\",  and no other arguments are needed anymore.\r
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