document.write( "Question 1207302: The lengths of the sides of an equilateral triangle are log4(a), log10(b), log25(a+b) where A and B are positive numbers. What is the value of a/b? \n" ); document.write( "
Algebra.Com's Answer #845095 by ikleyn(52792)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "The lengths of the sides of an equilateral triangle are log4(a), log10(b), log25(a+b)
\n" ); document.write( "where A and B are positive numbers. What is the value of a/b?
\n" ); document.write( "~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "We are given \r\n" );
document.write( "\r\n" );
document.write( "    \"log%284%2Ca%29\" = \"log%2810%2Cb%29\" = \"log%2825%2C%28a%2Bb%29%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Let  k = \"log%284%2Ca%29\" = \"log%2810%2Cb%29\" = \"log%2825%2C%28a%2Bb%29%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It means that \r\n" );
document.write( "\r\n" );
document.write( "    \"4%5Ek\" = a,       (1)\r\n" );
document.write( "\r\n" );
document.write( "    \"10%5Ek\" = b,      (2)\r\n" );
document.write( "\r\n" );
document.write( "    \"25%5Ek\" = a + b.  (3)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It implies that\r\n" );
document.write( "\r\n" );
document.write( "    \"4%5Ek\" + \"10%5Ek\" = \"25%5Ek\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides (all the terms) by  \"25%5Ek\".  You will get\r\n" );
document.write( "\r\n" );
document.write( "    \"%284%2F25%29%5Ek\" + \"%2810%2F25%29%5Ek\" = 1,\r\n" );
document.write( "\r\n" );
document.write( "or\r\n" );
document.write( "\r\n" );
document.write( "    \"%282%2F5%29%5E%282k%29\" + \"%282%2F5%29%5Ek\" = 1.    (4)\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Let x = \"%282%2F5%29%5Ek\".  Then equation (4) takes the form\r\n" );
document.write( "\r\n" );
document.write( "    \"x%5E2\" + x = 1,\r\n" );
document.write( "\r\n" );
document.write( "or\r\n" );
document.write( "\r\n" );
document.write( "    \"x%5E2\" + x - 1 = 0.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Its roots are  \"x%5B1%5D\" = \"%28-1+%2B+sqrt%285%29%29%2F2\",  \"x%5B2%5D\" = \"%28-1+-+sqrt%285%29%29%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Our value of x is positive \"%282%2F5%29%5Ek\";  so, we consider only positive root  x = \"%28sqrt%285%29-1%29%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Thus we have\r\n" );
document.write( "\r\n" );
document.write( "    \"%282%2F5%29%5Ek\" = \"%28sqrt%285%29-1%29%2F2\",\r\n" );
document.write( "\r\n" );
document.write( "or\r\n" );
document.write( "\r\n" );
document.write( "    \"%284%2F10%29%5Ek\" = \"%28sqrt%285%29-1%29%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "But from (1) and (2),  \"a%2Fb\" = \"%284%2F10%29%5Ek\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Thus we proved that  \"a%2Fb\" = \"%28sqrt%285%29-1%29%2F2\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  \"a%2Fb\" = \"%28sqrt%285%29-1%29%2F2\" = 0.618033989  (approximately).\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );