Algebra.Com's Answer #845095 by ikleyn(52792)  You can put this solution on YOUR website! . \n" );
document.write( "The lengths of the sides of an equilateral triangle are log4(a), log10(b), log25(a+b) \n" );
document.write( "where A and B are positive numbers. What is the value of a/b? \n" );
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document.write( "We are given \r\n" );
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document.write( " = = .\r\n" );
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document.write( "Let k = = = .\r\n" );
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document.write( "It means that \r\n" );
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document.write( " = a, (1)\r\n" );
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document.write( " = b, (2)\r\n" );
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document.write( " = a + b. (3)\r\n" );
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document.write( "It implies that\r\n" );
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document.write( " + = .\r\n" );
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document.write( "Divide both sides (all the terms) by . You will get\r\n" );
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document.write( " + = 1,\r\n" );
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document.write( "or\r\n" );
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document.write( " + = 1. (4)\r\n" );
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document.write( "Let x = . Then equation (4) takes the form\r\n" );
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document.write( " + x = 1,\r\n" );
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document.write( "or\r\n" );
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document.write( " + x - 1 = 0.\r\n" );
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document.write( "Its roots are = , = .\r\n" );
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document.write( "Our value of x is positive ; so, we consider only positive root x = .\r\n" );
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document.write( "Thus we have\r\n" );
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document.write( " = ,\r\n" );
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document.write( "or\r\n" );
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document.write( " = .\r\n" );
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document.write( "But from (1) and (2), = .\r\n" );
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document.write( "Thus we proved that = .\r\n" );
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document.write( "ANSWER. = = 0.618033989 (approximately).\r\n" );
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document.write( "Solved.\r \n" );
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