document.write( "Question 1207300: A company that manufactures dog food wishes to pack in closed cylindrical tins.
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Algebra.Com's Answer #845092 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "A company that manufactures dog food wishes to pack in closed cylindrical tins.\r\n" );
document.write( "What should be the dimensions of each tin if it is to have a volume of\r\n" );
document.write( "128πcm³ and the minimum possible surface area:\r\n" );
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document.write( "In the UK, you say \"tin\". In the US, we say \"can\". LOL \r\n" );
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document.write( "The volume of a cylinder is \r\n" );
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document.write( "\"V+=+pi%2Ar%5E2%2Ah+=+128%2Api\" \r\n" );
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document.write( "Which simplifies to \r\n" );
document.write( "\"r%5E2%2Ah=128\" \r\n" );
document.write( "\"h=128%5E%22%22%2Fr%5E2\"\r\n" );
document.write( "The surface area of a cylinder with a top and bottom is\r\n" );
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document.write( "\"A+=+2%2Api%2Ar%2Ah%2B2pi%2Ar%5E2\"\r\n" );
document.write( "Substituting for h:\r\n" );
document.write( "\"A+=+2%2Api%2Ar%28128%5E%22%22%2Fr%5E2%29%2B2%2Api%2Ar%5E2\"\r\n" );
document.write( "\"A+=+%28256%2Api%29%2Fr+%2B+2%2Api%2Ar%5E2\"\r\n" );
document.write( "\"A+=+256%2Api%2Ar%5E%28-1%29+%2B+2%2Api%2Ar%5E2\"\r\n" );
document.write( "Differentiating w/r r:\r\n" );
document.write( "\"dA%2Fdr=-256%2Api%2Ar%5E%28-2%29%2B4%2Api%2Ar\"\r\n" );
document.write( "Setting the derivative equal to zero:\r\n" );
document.write( "\"-256%2Api%2Ar%5E%28-2%29%2B4%2Api%2Ar=0\"\r\n" );
document.write( "Dividing through by -4π\r\n" );
document.write( "\"64r%5E%28-2%29-r=0\"\r\n" );
document.write( "Multiplying through by r2\r\n" );
document.write( "\"64-r%5E3=0\"\r\n" );
document.write( "\"64=r%5E3\"\r\n" );
document.write( "\"4=r\"\r\n" );
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document.write( "So the radius of each can should be 4 cm. (diameter = 8 cm.)\r\n" );
document.write( "Substituting in\r\n" );
document.write( "\"r%5E2%2Ah=128\"\r\n" );
document.write( "\"4%5E2%2Ah=128\"\r\n" );
document.write( "\"16%2Ah=128\"\r\n" );
document.write( "\"h=8\"\r\n" );
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document.write( "And the height of each can should be 8 cm.\r\n" );
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document.write( "So the mid-cross section of each can should be an 8 cm x 8 cm square!\r\n" );
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document.write( "Edwin
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