document.write( "Question 1207300: A company that manufactures dog food wishes to pack in closed cylindrical tins.
\n" ); document.write( "What should be the dimensions of each tin if it is to have a volume of 128πcm³
\n" ); document.write( "and the minimum possible surface area?
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Algebra.Com's Answer #845091 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The volume of the cylindrical can with radius r and height h is to be 128pi cm^3:

\n" ); document.write( "\"V=%28pi%29r%5E2h=128pi\" [1]

\n" ); document.write( "The surface area of the can -- top, bottom, and side -- is

\n" ); document.write( "\"S=2%28pi%29r%5E2%2B2%28pi%29rh\" [2]

\n" ); document.write( "Solve [1] for h in terms of r and substitute in [2] to get an expression for the surface area in terms of the single variable r:

\n" ); document.write( "\"h=128%2Fr%5E2\"
\n" ); document.write( "\"S=2%28pi%29r%5E2%2B2%28pi%29r%28128%2Fr%5E2%29=2%28pi%29r%5E2%2B256%28pi%29%2Fr\"

\n" ); document.write( "Find the derivative of the expression for the surface area and set it equal to zero to find the radius r that minimizes the surface area:

\n" ); document.write( "\"dS%2Fdr=4%28pi%29r-256%28pi%29%2Fr%5E2\"
\n" ); document.write( "\"4%28pi%29r-256%28pi%29%2Fr%5E2=0\"
\n" ); document.write( "\"4%28pi%29%28r-64%2Fr%5E2%29=0\"
\n" ); document.write( "\"r-64%2Fr%5E2=0\"
\n" ); document.write( "\"r%5E3-64=0\"
\n" ); document.write( "\"r=4\"

\n" ); document.write( "The radius that minimizes the surface area is r=4; the corresponding height is 128/r^2 = 128/16 = 8.

\n" ); document.write( "ANSWER: radius 4cm, height 8cm

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