document.write( "Question 1207301: Hi
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document.write( "A baby pool with 4350 litres needs to be filled. Water from hose A has a rate of
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document.write( "150 litres per minute while hose B 250 litres per minute. If A is turned on 3
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document.write( "minutes after B is turned on how long will it take to fill up the pool?
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document.write( "Thanks \n" );
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Algebra.Com's Answer #845089 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! Hi \n" ); document.write( "A baby pool with 4350 litres needs to be filled. Water from hose A has a rate \n" ); document.write( "of 150 litres per minute while hose B 250 litres per minute. If A is turned on \n" ); document.write( "3 minutes after B is turned on how long will it take to fill up the pool? \n" ); document.write( "Thanks. \n" ); document.write( " \r\n" ); document.write( "Hose B pours water in the pool for 3 minutes alone, at the rate of 250 liters\r\n" ); document.write( "per minutes. Therefore, hose B pours in (3)(250)=750 liters before A is turned\r\n" ); document.write( "on.\r\n" ); document.write( "\r\n" ); document.write( "Then there are 4350-750=3600 more liters to fill in.\r\n" ); document.write( "\r\n" ); document.write( "Now hose A and hose B's combined filling rate is the sum of their individual\r\n" ); document.write( "filling rates, or 150+250=400 liters per minute.\r\n" ); document.write( "\r\n" ); document.write( "So\n" ); document.write( " |