document.write( "Question 1207301: Hi
\n" ); document.write( "A baby pool with 4350 litres needs to be filled. Water from hose A has a rate of
\n" ); document.write( "150 litres per minute while hose B 250 litres per minute. If A is turned on 3
\n" ); document.write( "minutes after B is turned on how long will it take to fill up the pool?
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Algebra.Com's Answer #845089 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
Hi
\n" ); document.write( "A baby pool with 4350 litres needs to be filled. Water from hose A has a rate
\n" ); document.write( "of 150 litres per minute while hose B 250 litres per minute. If A is turned on
\n" ); document.write( "3 minutes after B is turned on how long will it take to fill up the pool?
\n" ); document.write( "Thanks.
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document.write( "Hose B pours water in the pool for 3 minutes alone, at the rate of 250 liters\r\n" );
document.write( "per minutes.  Therefore, hose B pours in (3)(250)=750 liters before A is turned\r\n" );
document.write( "on.\r\n" );
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document.write( "Then there are 4350-750=3600 more liters to fill in.\r\n" );
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document.write( "Now hose A and hose B's combined filling rate is the sum of their individual\r\n" );
document.write( "filling rates, or 150+250=400 liters per minute.\r\n" );
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document.write( "So \"matrix%281%2C2%2C3600%2C+liters%29%2Fmatrix%281%2C4%2C400%2Cliters%2Cper%2Cminute%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C9%2Cminutes%29\" \r\n" );
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document.write( "to finish filling the pool.\r\n" );
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document.write( "So the total time is 3+9=12 minutes.\r\n" );
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document.write( "Edwin
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