document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207292>Question 1207292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 360L of paint is made by mixing 3 paints A, B C . the ratio by amount of paint A to B is 3:2 and that of B to C is 1:2 Paint A costs 1800 per liter Paint B costs 2400 per liter and Paint C 1275 per litre . find the amount of each paint , the amount of money needed to make one liter of the mixture </SPAN>\n" );
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document.write( "The ratio of A to B is 3:2.  A:B=3:2<br><BR>\n" );
document.write( "The ratio of B to C is 1:2.  B:C=1:2<br><BR>\n" );
document.write( "Scale the second ratio up to make the same number for B in both ratios.  B:C=2:4<br><BR>\n" );
document.write( "Write a compound statement showing the ratios of all three.  A:B:C=3:2:4<br><BR>\n" );
document.write( "So paint A is 3/9 of the mixture, paint B is 2/9, and paint C is 4/9.<br><BR>\n" );
document.write( "The mixture is 360L, so<BR>\n" );
document.write( "A = (3/9)360 = 3*40 = 120L<BR>\n" );
document.write( "B = (2/9)360 = 2*40 = 80L<BR>\n" );
document.write( "C = (4/9)360 = 4*40 = 160L<br><BR>\n" );
document.write( "We can use the fractions of the mixture that each paint is, along with the cost per liter of each paint, to find the cost of one liter of the mixture as a weighted average:<br><BR>\n" );
document.write( "(3/9)(1800)+(2/9)(2400)+(4/9)(1275)=(5400+4800+5100)/9 = 15300/9 = 1700<br><BR>\n" );
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