document.write( "Question 1207295: A veterinarian wishes to use 156 feet of chain-link fencing to enclose a rectangular region and subdivide the region into two smaller rectangular regions, as shown in the following figure. If the total enclosed area is 864 square feet, find the width w and length l of the enclosed region.\r
\n" ); document.write( "\n" ); document.write( "w = ft (smaller width) by l = ft
\n" ); document.write( "w = ft (larger width) by l = ft
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Algebra.Com's Answer #845082 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The lengths of fencing are the width 3 times and the length 2 times; the total is 156 feet: \"3w%2B2l=156\"

\n" ); document.write( "The area of 864 square feet is length times width: \"lw=864\"

\n" ); document.write( "Solve the first equation for the width w and substitute in the second equation.

\n" ); document.write( "\"3w=156-2l\"
\n" ); document.write( "\"w=%28156-2l%29%2F3\"
\n" ); document.write( "\"l%28%28156-2l%29%2F3%29=864\"
\n" ); document.write( "\"156l-2l%5E2=2592\"
\n" ); document.write( "\"2l%5E2-156l%2B2592=0\"
\n" ); document.write( "\"l%5E2-78l%2B1296=0\"
\n" ); document.write( "\"%28l-24%29%28l-54%29=0\"

\n" ); document.write( "\"l=24\" or \"l=54\"

\n" ); document.write( "If \"l=24\" then \"w=%28156-48%29%2F3=36\"

\n" ); document.write( "First solution: length 24, width 36
\n" ); document.write( "CHECK: 24*36=864; 3(36)+2(24)=108+48=156

\n" ); document.write( "If \"l=54\" then \"w=%28156-108%29%2F3=16\"

\n" ); document.write( "Second solution: length 54, width 16
\n" ); document.write( "CHECK: 54*16=864; 3(16)+2(54)=48+108=156

\n" ); document.write( "ANSWERS:
\n" ); document.write( "(1) width 36, length 24
\n" ); document.write( "(2) width 16, length 54

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