document.write( "Question 1207294: Write the equation of the line in standard form with y-intercept 3 and a slope of -2/3.
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Algebra.Com's Answer #845080 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( " the equation of the line in standard form \r
\n" ); document.write( "\n" ); document.write( "\"ax%2Bby=c\"\r
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( " y-intercept \"3\" => point (\"0\",\"3\")\r
\n" ); document.write( "\n" ); document.write( " a slope of \"m=-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "using point slope form we have\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"....substitute given values\r
\n" ); document.write( "\n" ); document.write( "\"y-3=-%282%2F3%29%28x-0%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-3=-%282%2F3%29x\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-%282%2F3%29x%2B3\"...both sides multiply by \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"3y=-2x%2B9\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B3y=9\" => your equation\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-%282%2F3%29x%2B3%29+\"\r
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