document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1207292>Question 1207292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 360L of paint is made by mixing 3 paints A, B C . the ratio by amount of paint A to B is 3:2 and that of B to C is 1:2 Paint A costs 1800 per liter Paint B costs 2400 per liter and Paint C 1275 per litre . find the amount of each paint , the amount of money needed to make one liter of the mixture </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #845077 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=845077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = number of liters of paint A.<BR>\n" );
document.write( "b = number of liters of paint B.<BR>\n" );
document.write( "c = number of liters of paint C.\r<BR>\n" );
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document.write( "you have a + b + c = 360.\r<BR>\n" );
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document.write( "a/b = 3/2.<BR>\n" );
document.write( "cross multiply to get 2a = 3b\r<BR>\n" );
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document.write( "b/c = 1/2.<BR>\n" );
document.write( "cross multiply to get 2b = c.\r<BR>\n" );
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document.write( "solve in terms of b for all ratios.<BR>\n" );
document.write( "2a = 3b gets you a = 3b/2.<BR>\n" );
document.write( "c = 2b gets you c = 2b.\r<BR>\n" );
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document.write( "a + b + c = 360 becomes 3b/2 + b + 2b = 360 after replacing a and c with their equivalent values in terms of b.<BR>\n" );
document.write( "multiply both sides of that equation by 2 to get 3b + 2b + 4b = 720<BR>\n" );
document.write( "combine like terms to get 9b = 720.<BR>\n" );
document.write( "solve for b to get b = 720 / 9 = 80.\r<BR>\n" );
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document.write( "you have a = 3b/2 = 3*80/2 = 120.<BR>\n" );
document.write( "b = 80.<BR>\n" );
document.write( "c = 2b = 2*80 = 160.\r<BR>\n" );
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document.write( "a = 120, b = 80, c = 160.<BR>\n" );
document.write( "a + b + c = 120 + 80 + 160 = 360.\r<BR>\n" );
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document.write( "A is 1800 per liter.<BR>\n" );
document.write( "B is 2400 per liter.<BR>\n" );
document.write( "C is 1275 per liter.\r<BR>\n" );
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document.write( "total price is 120 * 1800 + 80 * 2400 + 160 * 1275 = 612000.<BR>\n" );
document.write( "612000 / 360 = 1700 per liter.\r<BR>\n" );
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document.write( "that's your solution.<BR>\n" );
document.write( "1 liter of the mix would cost 1700.\r<BR>\n" );
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