document.write( "Question 1207285: A model rocket is launched upward with an initial velocity of 270 feet per second. The height, in feet, of the rocket t seconds after the launch is given by
\n" ); document.write( "h = −16t2 + 270t.
\n" ); document.write( "How many seconds after the launch will the rocket be 390 feet above the ground? Round to the nearest tenth of a second.
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Algebra.Com's Answer #845067 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"h+=+-16t%5E2+%2B+270t\"\r
\n" ); document.write( "\n" ); document.write( "Now, we have to find out the time when \"h+=+390\" feet.\r
\n" ); document.write( "\n" ); document.write( "\"390+=+-16t%5E2+%2B+270t\"\r
\n" ); document.write( "\n" ); document.write( "\"390+%2B16t%5E2+-+270t=0\"\r
\n" ); document.write( "\n" ); document.write( "\"16t%5E2+-+270t%2B390+=0\"\r
\n" ); document.write( "\n" ); document.write( "\"t=%28-%28-270%29%2B-sqrt%28%28-270%29%5E2-4%2A16%2A390%29%29%2F%282%2A16%29\"\r
\n" ); document.write( "\n" ); document.write( "\"t=%28270%2B-sqrt%2847940%29%29%2F32\"\r
\n" ); document.write( "\n" ); document.write( "\"t=%28270%2B-218.95%29%2F32\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=1.6\" or \"t=15.3\"\r
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\n" ); document.write( "\n" ); document.write( "answer is:
\n" ); document.write( " the rocket will be \"390\" feet above the ground\r
\n" ); document.write( "\n" ); document.write( "in \"t=1.6\" seconds on the way up, and\r
\n" ); document.write( "\n" ); document.write( "in \"t=15.3\" seconds on the way down\r
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