document.write( "Question 1200393: If n=440 and X = 352, construct a 99% confidence interval.\r
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document.write( "Give your answers to three decimals\r
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document.write( " ______< p <_______
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Algebra.Com's Answer #845046 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor has made a few mistakes.
\n" ); document.write( "phat = sample proportion \n" ); document.write( "phat = (number of successes)/(sample size) \n" ); document.write( "phat = x/n \n" ); document.write( "phat = 352/440 \n" ); document.write( "phat = 0.8 exactly \n" ); document.write( "This is the center of the confidence interval. \n" ); document.write( "The job of phat is to estimate the population proportion p.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 99% confidence, the z critical value is roughly z = 2.576 \n" ); document.write( "This value is to either be memorized or looked up on a reference sheet. \n" ); document.write( "The back of your stats textbook will have the necessary table of values. \n" ); document.write( "Your stats professor may let you have a notecard for exams, or perhaps hand out reference sheets for exams.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "E = margin of error for a proportion \n" ); document.write( "E = z*sqrt(phat*(1-phat)/n) \n" ); document.write( "E = 2.576*sqrt(0.8*(1-0.8)/440) \n" ); document.write( "E = 0.049122392598 approximately \n" ); document.write( "E = 0.049122\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = lower boundary of confidence interval \n" ); document.write( "L = phat - E \n" ); document.write( "L = 0.8 - 0.049122 \n" ); document.write( "L = 0.750878 \n" ); document.write( "L = 0.751\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = upper boundary of confidence interval \n" ); document.write( "U = phat + E \n" ); document.write( "U = 0.8 + 0.049122 \n" ); document.write( "U = 0.849122 \n" ); document.write( "U = 0.849\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The values of L and U are approximate.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 99% confidence interval of the format L < p < U is therefore approximately 0.751 < p < 0.849 when rounding to 3 decimal places. \n" ); document.write( "Many stats calculators can be used to confirm this solution. \n" ); document.write( " \n" ); document.write( " |