document.write( "Question 1207243: A money box contained some money at first. A took 1/2 the amount of money and another $1500 from the box. After that, B took 1/4 of the remaining amount of money and another $850 from the box. In the end, C took the rest of the money left in the box. Given that C took $1400, find the amount of money in the box at first. \n" ); document.write( "
Algebra.Com's Answer #845018 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This kind of problem is often solved more easily by working backwards, as described below. \n" ); document.write( "C got $1400. \n" ); document.write( "Just before that, B took $850; so before B took $850 the amount was $1400+$850 = $2250. \n" ); document.write( "Just before that, B took 1/4 of the money; that means the $2250 was 3/4 of the money that there was before. So the amount of money before B took 1/4 of it was $2250*(4/3) = $3000. \n" ); document.write( "Just before that, A took $1500; so before A did that the amount was $3000+$1500 = $4500. \n" ); document.write( "And just before that, A took 1/2 of the initial amount; that means the $4500 left after he took 1/2 of the money was also 1/2 of the money. So the initial amount of money was $4500*(2/1) = $9000. \n" ); document.write( "ANSWER: $9000 \n" ); document.write( "CHECK: \n" ); document.write( "$9000 minus 1/2 of $9000 = $9000-$4500 = $4500 \n" ); document.write( "$4500-$1500 = $3000 \n" ); document.write( "$3000 - 1/4 of $3000 = $3000-$750 = $2250 \n" ); document.write( "$2250-$850 = $1400 \n" ); document.write( " \n" ); document.write( " |