document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=116182>Question 116182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem. A boat can go 33 mph in still water. It takes as long to go 300 miles upstream as it does to go downstream 360 miles. How fast is the current?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #84500 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=84500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 300/(33-C)=360/(33+C) CROSS MULTIPLY.<BR>\n" );
document.write( "360(33-C)=300(33+C)<BR>\n" );
document.write( "11880-360C=9900+300C<BR>\n" );
document.write( "-360C-300C=9900-11880<BR>\n" );
document.write( "-660C=-1980<BR>\n" );
document.write( "C=-1980/-660<BR>\n" );
document.write( "C=3 MPH IS THE SPEED OF THE CURRENT.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "300/(33-3)=360/(33+3)<BR>\n" );
document.write( "300/30=360/36<BR>\n" );
document.write( "10=10\r<BR>\n" );
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document.write( " </SPAN>\n" );
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