document.write( "Question 1207198: Billy invested in a savings account for 3 years and was paid an annual rate of 4%. The total interest that he earned was $72. How much did he invest? \n" ); document.write( "
Algebra.Com's Answer #844937 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Find the principal by using the formula \r
\n" ); document.write( "\n" ); document.write( "\"I=P%2Ai%2At\" , where \"I\" is interest, \"P\" is total principal, \"i\" is rate of interest per year, and \"t\" is total time in years\r
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\n" ); document.write( "\n" ); document.write( "In this example \"I+=+72\", \"i+=+4\"% =\"0.04\" and \"t+=+3+\"years, so\r
\n" ); document.write( "\n" ); document.write( "\"I=P%2Ai%2At\"....solve for \"P\"\r
\n" ); document.write( "\n" ); document.write( "\"P=+I%2F%28i%2At%29\"...substitute given\r
\n" ); document.write( "\n" ); document.write( "\"P=+72%2F%280.04%2A3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=+72%2F%280.12%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=+7200%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"P=+600\"\r
\n" ); document.write( "\n" ); document.write( "Billy invested $\"600\".\r
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