document.write( "Question 1207186:  The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to drive from City A to City B and takes 1.6 hours to drive from City B to City C. Find the distance from City A to City C. (Neglect the curvature of the earth.)
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| Algebra.Com's Answer #844922 by mananth(16946)     You can put this solution on YOUR website! The bearing from City A to City B is Upper N 41 degrees Upper E. The bearing from City B to City C is Upper S 49 degrees Upper E. An automobile driven at 65 mph takes 1.4 hours to drive from City A to City B and takes 1.6 hours to drive from City B to City C. Find the distance from City A to City C. (Neglect the curvature of the earth.)\r \n" ); document.write( "\n" ); document.write( "From A to B \n" ); document.write( "Distance \r \n" ); document.write( "\n" ); document.write( "65*1.4 = 91 miles\r \n" ); document.write( "\n" ); document.write( "From B to C \n" ); document.write( "65*1.6 = 104 miles\r \n" ); document.write( "\n" ); document.write( "Now the angle ABC (49+41)=90 deg by geometry (parallel lines and transversal)\r \n" ); document.write( "\n" ); document.write( "AC^2 = AB^2 +BC^2\r \n" ); document.write( "\n" ); document.write( "AC^2 = 91^2+104^2\r \n" ); document.write( "\n" ); document.write( "AC = sqrt(91^2+104^2)\r \n" ); document.write( "\n" ); document.write( "  \n" );
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