document.write( "Question 1207173: Question content area top
\n" ); document.write( "Part 1
\n" ); document.write( "A person invested ​$6900 for 1​ year, part at 8​%, part at 11​%, and the remainder at 14​%. The total annual income from these investments was ​$834. The amount of money invested at 14% was ​$900 more than the amounts invested at 8​% and 11​% combined. Find the amount invested at each rate.
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Algebra.Com's Answer #844915 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There are always different ways to set up a problem for solving.

\n" ); document.write( "The method shown by the other tutor basically translates the given information directly into equations that are then solved to find the answer.

\n" ); document.write( "I think a very different approach, analyzing the given information to find a way to set up the problem that makes solving the problem easier, is better.

\n" ); document.write( "Given that the total invested was $6900 and that the amount invested at 14% was $900 more than the combined amounts invested at 8% and 11%, we can quickly determine that $3900 was invested at 14% and $3000 combined at 8% and 11%. I leave the details for finding that result to the student, if formal algebra is required.

\n" ); document.write( "$3900 invested at 14% yields $546 income; that leaves $834-$546 = $288 income from the other two investments.

\n" ); document.write( "A standard formal solution for that part of the problem would start something like this:

\n" ); document.write( "x = amount invested at 8%
\n" ); document.write( "3000-x = amount invested at 11%

\n" ); document.write( "The total income from those two investments was $288:

\n" ); document.write( ".08(x)+.11(3000-x)=288

\n" ); document.write( "Solving that equation then finishes the problem.

\n" ); document.write( "I use a different, less formal method for solving 2-part \"mixture\" problems like this. Here is my method for solving this part of the problem.

\n" ); document.write( "All $3000 invested at 8% would yield $240 income; all invested at 11% would yield $330 income; the actual income from those two investments was $288.
\n" ); document.write( "Look at those three numbers 240, 288, and 330 (on a number line, if it helps), and observe/calculate that 288 is 48/90 = 8/15 of the way from 240 to 330.
\n" ); document.write( "That means 8/15 of the $3000 was invested at the higher rate.

\n" ); document.write( "8/15 of $3000 is 8*$200 = $1600, so $1600 was invested at 11% and $1400 at 8%.

\n" ); document.write( "ANSWERS: $3900 at 14%, $1600 at 11%, and $1400 at 8%

\n" ); document.write( "CHECK: .14(3900)+.11(1600)+.08(1400) = 546+176+112 = 834

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