document.write( "Question 1207168: Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -2.572°C and -0.181°C \n" ); document.write( "
Algebra.Com's Answer #844886 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the mean is 0 and the standard deviation is 1 degrees \n" ); document.write( "the probabiliy you'll get a reading between -2.572 degrees and -0.181 degrees can be found using the z-score as follows.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score formuls is z = (x-m)/s \n" ); document.write( "z is the z-score \n" ); document.write( "x is the critical low score or the critical high score. \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the low score, the formula becomes z = (-2.572 - 0) / 1 = -2.572. \n" ); document.write( "using the high score, the formula becomes z = -.181 - 0) / 1 = -.181.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can use a z-score calculator to find that the area to the left of the z-score of -2.572 is equal to .0050556733 and the area to the left of the z-score of -.181 is equal to .428183948. \n" ); document.write( "the area in between is the larger area minus the smaller area equal to .4231281215.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the probability that the temperature will be between -2.572 degrees and -.181 degrees centigrade.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "some calculators allow you to find it directly, without having to use the z-scorfes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "one such calculator canb e found at https://www.hackmath.net/en/calculator/normal-distribution?mean=3510&sd=25&above=3485&area=below&below=3485&ll=&ul=&outsideLL=&outsideUL=&draw=Calculate\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with this calculator, you enter the mean and the standard deviation and the low and high score desired and it tells you the probability.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here are the results.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you wanted the z-score, rather than the raw score, you would have entered a mean of 0 and a standard deviation of 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this problem is unique in that the z-score has a mean of 0 and a standard deviation of 1 and also has a raw score with a mean of 0 and a standard deviation of 1. \n" ); document.write( "that is not usually the case.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |