document.write( "Question 1207165: Chris has invented a new app for smart phones that two companies are interested in purchasing for a 2-year contract.
\n" ); document.write( "Company A is offering her $10,000 for the first month and will increase the amount each month by $5000.
\n" ); document.write( "Company B is offering $500 for the first month and will double their payment each month from the previous month.
\n" ); document.write( "Monthly payments are made at the end of each month. For which monthly payment will company B’s payment first exceed company A’s payment?
\n" ); document.write( "A. 6
\n" ); document.write( "B. 7
\n" ); document.write( "C. 8
\n" ); document.write( "D. 9
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Algebra.Com's Answer #844884 by mananth(16946)\"\" \"About 
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Chris has invented a new app for smart phones that two companies are interested in purchasing for a 2-year contract.
\n" ); document.write( "Company A is offering her $10,000 for the first month and will increase the amount each month by $5000.
\n" ); document.write( "Company B is offering $500 for the first month and will double their payment each month from the previous month.
\n" ); document.write( "Monthly payments are made at the end of each month. For which monthly payment will company B’s payment first exceed company A’s payment?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Company A is offering her $10,000 for the first month and will increase the amount each month by $5000.
\n" ); document.write( "Every month there is an increase of $5000. (fixed)
\n" ); document.write( "We use a(n) formula of arithmetic squence.
\n" ); document.write( "Let n be the number of months when salary of B greater than that of A\r
\n" ); document.write( "\n" ); document.write( "a(n)= 10000+ (n-1)*5000\r
\n" ); document.write( "\n" ); document.write( "a(n) = 10000+5000n-5000 = 5000+5000n\r
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\n" ); document.write( "\n" ); document.write( "Company B is offering $500 for the first month and will double their payment each month from the previous month.\r
\n" ); document.write( "\n" ); document.write( "Here it forms a geometric sequence with ratio r=2
\n" ); document.write( "a=500\r
\n" ); document.write( "\n" ); document.write( "a(n) = 500*2^(n-1)\r
\n" ); document.write( "\n" ); document.write( "500*2^(n-1) >5000+5000n\r
\n" ); document.write( "\n" ); document.write( "2^(n-1) >10+10n\r
\n" ); document.write( "\n" ); document.write( "Find n using calculator to find when B's salary will be higher than A's\r
\n" ); document.write( "\n" ); document.write( "or plug n = 5,6,7,8,9 to find the correct choice\r
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